Matematika Sekolah Menengah Atas tolong bantu jawab terimakasih
[tex] {18}^{3} - {6}^{2} + \sqrt[3]{110.592} \div \sqrt{144} = [/tex]

tolong bantu jawab terimakasih
[tex] {18}^{3} - {6}^{2} + \sqrt[3]{110.592} \div \sqrt{144} = [/tex]

[tex] {18}^{3} = 18 \times 18 \times 18[/tex]

[tex] = 5.832[/tex]

[tex] {6}^{2} = 6 \times 6 = 36[/tex]

[tex] \sqrt[3]{110.592} = 48[/tex]

[tex] {48}^{3} = 48 \times 48 \times 48 = 110.592[/tex]

[tex] \sqrt{144} = 12[/tex]

[tex] {12}^{2} = 12 \times 12 = 144[/tex]

[tex] \blue{jawab:}[/tex]

[tex] {18}^{3} - {6}^{2} + \sqrt[3]{110.592} \div \sqrt{144} [/tex]

[tex] =( 5.832 - 36) + (48 \div 12)[/tex]

[tex] = 5.796 + 4[/tex]

[tex] = 5.800[/tex]

Penjelasan dengan langkah-langkah:

[tex]\sf {18}^{3} - {6}^{2} + \sqrt[3]{110.592} \div \sqrt{144} =[/tex]

[tex]\sf = {18}^{3} - {6}^{2} + \sqrt[3]{ {48}^{3} } \div \sqrt{ {12}^{2} } [/tex]

[tex]\sf = (18 \times 18 \times 18) - (6 \times 6) + 48 \div 14[/tex]

[tex]\sf = (324 \times 18) - 36 + 48 \div 12[/tex]

[tex]\sf = 5.832 - 36 + (48 \div 12)[/tex]

[tex]\sf = 5.832 - 36 + 4[/tex]

[tex]\sf = 5.796 + 4[/tex]

[tex]\sf = 5.800[/tex]

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